Multiple else if

PHP
1

The following code should get a query (addressed to amazon ads) to get a link with author only if author is not AA.VV. (in Italian → autori vari = several [various] authors). Otherwise it should search only for the title (in Amazon “AA.VV.” doesn’t work)

   if(($trad_titolo != '') and ($autore != 'AA.VV.')) {echo ", tr.it. <i>$row[trad_titolo]</i>, $row[trad_edizione], $row[trad_luogo] $row[trad_data] (<a rel=\"external\" href=\"$myamzcode1=$amztitolotrad$myamzcode2";}
   else {echo ", tr.it. <i>$row[trad_titolo]</i>, $row[trad_edizione], $row[trad_luogo] $row[trad_data] (<a rel=\"external\" $myamzcode1=$amztitolotradAAVV$myamzcode2";}
   //originale in italiano
   if(($trad_titolo = '') and ($autore != 'AA.VV.')) {echo "(<a rel=\"external\" href=\"$myamzcode1=$amztitolo$myamzcode2";}
   else {echo "(<a rel=\"external\" href=\"$myamzcode1=$amztitoloAAVV$myamzcode2";}

However I get a webpage with

  • two (identical) links to amazon
  • both with the title ($trad_titolo) and both without author ($autore)

You can see the output php source code of webpage

`

  • AA.VV., Martin Lutero, Milano 1985, tr.it. , , ((.

  • Roland Herbert Bainton, Here I Stand: A Life of Martin Luther, Nashville 1950, tr.it. Lutero, Einaudi, Torino 1960 ((.
    • `

    Where I’m wrong?

    EDIT

    Why the following code doesn’t work as expected?

       if(($trad_titolo != '') and ($autore != 'AA.VV.')) {echo ", tr.it. <i>$row[trad_titolo]</i>, $row[trad_edizione], $row[trad_luogo] $row[trad_data] (<a rel=\"external\" href=\"$myamzcode1=$amztitolotrad$myamzcode2";}
   else {echo ", tr.it. <i>$row[trad_titolo]</i>, $row[trad_edizione], $row[trad_luogo] $row[trad_data] (<a rel=\"external\" $myamzcode1=$amztitolotradAAVV$myamzcode2";}
   //originale in italiano
   if(($trad_titolo = '') and ($autore != 'AA.VV.')) {echo "(<a rel=\"external\" href=\"$myamzcode1=$amztitolo$myamzcode2";}
   else {echo "(<a rel=\"external\" href=\"$myamzcode1=$amztitoloAAVV$myamzcode2";}
    2

    Look verrry carefully here…

    1 Like
    3

    What do you mean? :slightly_smiling_face:

    4

    = (assignment) vs == (comparison).

    1 Like
    5

    Thank you. I tried with: ($trad_titolo = =''), but unsuccessfully …

    6

    Define ‘unsuccessfully’.
    Your code will spit out two links in all codepaths.

    1 Like
    7

    Yes: two links, while I need only one, the Italian one.

    8

    So why have you got two if’s?

    1 Like
    9

    I don’t know :neutral_face:

    Screenshot_20240503_134733
    Screenshot_20240503_134733961×396 122 KB

    10

    Well I cant answer for you why you have two ifs. You put them into the code, why did you put them there if you only want one?

    1 Like
    11

    Ah, sorry. I didn’t understand: you did mean two“if".
    I did several attempts…

    12

    Well, each of those will generate a link. So… keep the one you need to keep?

    1 Like
    13

    Indeed. It seems that this code works

       if(($trad_titolo != '') and ($autore != 'AA.VV.')) {echo ", tr.it. <i>$row[trad_titolo]</i>, $row[trad_edizione], $row[trad_luogo] $row[trad_data] (<a rel=\"external\" href=\"$myamzcode1=$amztitolotrad$myamzcode2";}
   else if (($trad_titolo != '') and ($autore == 'AA.VV.')) {echo ", tr.it. <i>$row[trad_titolo]</i>, $row[trad_edizione], $row[trad_luogo] $row[trad_data] (<a rel=\"external\" $myamzcode1=$amztitolotradAAVV$myamzcode2";}
   //originale in italiano
   else if(($trad_titolo == '') and ($autore != 'AA.VV.')) {echo "(<a rel=\"external\" href=\"$myamzcode1=$amztitolo$myamzcode2";}
   else {echo "(<a rel=\"external\" href=\"$myamzcode1=$amztitoloAAVV$myamzcode2";}

    Now I have lo leave, but after I will check again.
    Thank you so much!

    EDIT

    Yes, it works! :+1: :+1:
    Thank you very much!

    14

    I have not done much PHP but I doubt that = = is the same as ==. My guess is that = = is the same as = (2 assignments would be the same as 1). Also if there is no space in ='' (no space between the equal sign and the quote) then that would likely be a problem too.

    15

    The space between the equals gives an “unexpected token” error.
    It needs to be == and not = = for comparison.

    1 Like